Algebra Math Help

Simple algebra II problems help, I do not remember!?

These are problems that I do not remember, if you please help, thank you very much, job performance! Solve for Y 1. x = 12-x, 2. 3/2y-4 4/5x = 3. 2/3x 1 / 2y = 6 Solve the formula for solving the inequality variable http://img183.imageshack.us/my.php?image=solvenq6.jpg Indicated (write answers on a range!) EX. [2,3) 1. X-5 ≥ 6 2. 5x-1 ≥ 1 3. -2 <2x-5 <3 4. -4 <2-x <6 5. 3 ≤ ≤ five 1/2x-1 That's just a few problems of this problem Spreadsheet 100. Thanks! Please show work! Enjoy!

Solve for y 1. x = 12-xy xy add both sides + X 12 = x x factor x (1) = 12 divide both sides by x, y 1 = 12 / X subtract 1 from both sides y = 12 / -1 x The inequalities are solved in the same way. Whatever you do to one side, you have to do to another. The secret is to "undo" the equation until the variable to solve by itself. Sum "cancel" subtraction. Resta "cancels" the bill. Multiplication "cancels" the division and the division "cancels" multiplication. Here are some other examples, a so you can make yourself the rest. 3/2y-4 = 4/5x, add 4 to both sides (4.5) (x) 4 = 3 / 2 (And) what can be done in two stages, it is easier to multiply both sides by 2 8 / 5 (x) + 8 = 3 and now divide by 3 (8/5x + / 3 = o, a single step (4.5) (x) 4 = 3 / 2 (y) is divided by 3 / 2 y = ((8x 40) / 15)) 2. 5x-1 ≥ 1 subtract 1 from both sides-5x = 0 x> = 0 3. <-2 2x-5 <3 add May all parties 3 <2x <8 divide everything by 2 3 / 2 <x <4 Good luck.