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Algebra Formulas For Area

October 18th, 2010 admin Leave a comment Go to comments


Can someone help me solve these Algebra Problems?

1. (x-4) (2x-7)=0
2. x^2 + 5x -36=0
3. x^2 + 21=-10x
4. 4x^2=3x -12x^2
5. 4x^2 + 11x=2x^2 -15
6. 3x^2 – 25x +28 =0
7. x^2 -25 =0
8.. The area of a rectangle is 55 square meters. Find the length and width of the rectangle if its length is 6 meters greater than its width. Use an equation and the formula for area of a rectangle A = l × w.

1. Set each factor = 0.
x = 4 or 7/2

2. Factor: (x+9)(x-4) = 0
x = -9 or x = 4

3. Add 10x:

x^2 + 10x + 21 = 0
Factor: (x+7)(x+3) = 0
x = -7 or x = -3

4. Subtract 3x and add 12x^2:

16x^2 – 3x = 0
Factor out x: x(16x – 3) = 0
x = 0 or x = 3/16

5. Subtract 2x^2 and add 15:

2x^2 + 11x + 15 = 0
(2x + 5)(x + 3) = 0
x = -7/2 or x = -3

6. Factor:
(3x – 4)(x – 7) = 0
x = 4/3 or x = 7

7. (x+5)(x-5) = 0
x = -5 or x = 5

8. w(w+6) = 55
w^2 + 6w – 55 = 0
(w+11)(w- 5) = 0
w = -11 or w = 5

width cannot be negative, so w = 5
width 5 meter, length add 6 to get 11 meters.

Algebra Review 13.6 – Formulas

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