Algebra Help Completing The Square
Algebra 1 help test? completing the square, the solution by elimination, etc?
Okay so I'm studying for my exam algebra morning. and I have tons of questions … im not exactly what happens with flying colors. I need help figuring out how to make a few kinds of problems, including the following ordered pairs are solutions to their respective systems of equations? (-1, 5) 5x 2 y = 3x = 5-4 and 23, how do you go about the solution a? or these … "Resolve to local disposal 2x +5 y = 17 6x-5y =- 9 and finally," a term that is added to each side of the equation to solve completing the square? "3x (squared) +9 = 8 x any help would be majorly appreciated:]
___________________________________ (1) Is (-1.5) to the system 5x 2 y = 3x 5-4 y = 23 You could solve this system to see if you get (-1.5). Or, you can check to see if you get 5 and 23 to connect to x = -1 y = 5. 5x 2 y = 5 5 (-1) + 2 (5) = -5 + 10 = 5 ✔ 4-3x = 23 -3 (-1) + 4 (5) = 3 + 20 = 23 ✔ Therefore, (-1, 5) is the solution. A ← ______________________________________ (2) 2x +5 y = 17 6x-5y = -9 —– 8x + 0 = 8 ← added the two equations together to eliminate or 8x = 8 x = 1 x = 1 2x +5 and substitute = 17 for y. 2x +5 = 17 2 (1) + 2 + 5y = 17 5y = 17 5y = 15 y = 3 A (1.3) ___________________________________ (3) 3x ² + 9 x 8 = ← First, you need to obtain the coefficient of x 1 x ² ² + 3x = 8 / 3 ← divide both sides by 3 Now, to complete the square, you have to add both sides is the square of half of the coefficient of x, which is 3 in this problem. Therefore, adding (3.2) ² 9 / 4 on each side _______________________________________________________ ← A
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