Algebra Help Parabola
please help! SOO confused (algebra!) finding vertex of parabola?
i need a lot of help! right now in algebra we’re finding the vertex of a parabola. we’re given an equation, but i cannot seem to get the right answer! PLEASE HELP ME! it’s really bad that i dont know this, and i’m stressing out! here’s a sample problem:
y=-5x^2+10x+3
Please! help mee!
if you can, go step by step…
the vertex is at a point located on the axis of symmetry, if you think about it, it HAS to be, because the axis is where you can fold the paper and the lines will match up perfectly. since the vertex has no point on the opposite side of the axis of symmetry, it must be on that imaginary axis. the axis of symmetry can be found with the formula x = -B/2A where A and B are the coefficients of x^2 and x.
Therefore, your axis of symmetry is -10/2(-5) which is 1.
plug in 1 for x.
-5(1)^2 + 10(1) +3
-5 + 10 + 3 = 8.
so your vertex is at the point (1,8)
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