Algebra Math Help

Algebra II: The quadratic formula?

Anyone can take steps either with only one or two of these problems? Any help would be much appreciated! Solve using the quadratic formula: 6 x ^ 2-19x-7 = 0 1 =- 3x ^ 2-7x

Greetings, When ax ^ 2 + bx + c = 0 x = -b/2a + / – Sqrt (b ^ 2 – 4ac) / 2A 6x ^ 2 – 19x – 7 = 0, a = 6, b = -19, c = -7 x = 19/12 + / – sqrt (19 ^ 2 – 4 (6) (-7)) / 12 x = 19 / 2 + / – sqrt (529) / 12 x = 19/12 + / – 23/12 x = 42/12 or x = -4/12 x = 7 / 2 or x = -1 / 3 Greetings

Watch Video on The Quadratic Formula – Algebra Help

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