Algebra Help Variables
I need help with systems with three variables (algebra 2)?
2x + y = 9 x + 2z 2y + 3z = -3 = 15 I have a test next week and still I can not find a way to do this
Given: 2x + y = 9 → (1) x + 2z = -3 → (2) 2y + 3z = 15 → (3) (3) * 2 – (2) * 3 da: 6Z-3x + 4y – 6Z = 30 – (-9) = 3x-4 y = 39 → (4) (1) * 3 + (4) * 2 gives: 6x + 3y – 6x + 8y = 27 + 78 = 11y = 105 y = 105/11 or 105 = 105/11 and Substitute (1), we get x = ½ [(9-105) / 11] =- 3 / 11 x = -3/11 Substitute in (2), we obtain z = ½ [-3 + ( 3.11)] = -15/11 For So x = y = z = -15/11 -3/11 AJM 105/11
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