Algebra Help With Radicals
16) C, put them under there own radicans and simplify the answer, I always end up with 24 abd the square root of 8. I'm doing wrong! 15.) A rectangle is seven times more 11) When multiplying radicals, find perfect squares. A perfect square is a number that has a square root, as 4 and 16. (2 x 2 is 4 and 4 x 4 is 16.) 32 no a square root, so lets look at 144. If you do not know the top of the head, just guess and check. I know that 10 x 10 is 100, so I guess I would start from there. You must finally realize that 12 x 12 is 144, and voila, we have a winner. You can now rewite this as √ 32 x 12, since 144 = √ 12. Now let's look at 32 years. when he did, using 8 and 4. That works, but there are additional steps. I prefer to use the largest perfect square. In this case is 16. Since we are (4 x 4 = 16.) Therefore, we can write this √ 32, 4 x √ 2, or only 4 √ 2. Together, we have 4 √ 2 x 12. The last step is to multiply. 4 x 12 the length of a rectangle is seven times as long as the width. We will represent the width w. Since the length is 7 times longer than the width, w, which represent 7w length. Now our equation is xw 7w = 1400. From here you just solve algebraically. 7w 7w = xw ^ 2, so we now have 7w ^ 2 = 1400. Now we have to get the variable itself, so divide both sides by 7. So now we are in w ^ 2 = 200. To get rid of the exponent, we find the square root of each side. 15) As this is algebra, we can easily assume that you have to write this problem as an equation. We know that the length of a rectangle is seven times more is longer than wide. We will represent the width and x. Since the length is 7 times longer than wide, ox, would represent the length 7x. Now our equation is xw 7w = 1400. From here you just solve algebraically. 7w 7w = xw ^ 2, so we now have 7w ^ 2 = 1400. Now we have is 10 √ 2, and the length is 70 √ 2.
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