Algebra Problems Coins
I need help with algebra 2 problems please?
Paula has an $ 8 in nickels and Dimes. In total there are 100 pieces. How many of each type of coin does she have? I do not understand how to solve this problem. I do not know what method to use. # 2 George five times as many sectors and dimes. which has 180 pieces from his collection. how many pieces of each type you have? same thing … I do not understand how to solve this problem. well, Thanks Please show your work, not just the answer! Thank you !!!!!!=]
0.05x + 0.10y = $ 8.00 x + y = 100 1100 to get rid of the decimal * (0.05x) + 100 * (0.10) = 100 * 100 * 8.0 (x) + 100 * ( y) = 100 * 100 gives 5x + 10Y + 100Y = 800 100x = 10,000 2. Deleting a variable having the other variable = 0 and the solution of this case x is the easiest -10 * (5x) + (-10 * (10 years)) = -10 100x + 800 * 100Y = 10000-50x – 100x + 100Y 100Y = 8000 50x + 0y = 10,000 = 2,000 x 2.000 = 50x = 40 3. By substituting New simplest is to replace in the formula x + y = y + 100 40 = 100 y = 100 = 40 Y = 60 4. Check Answer 05 * (40) + 0.1 * (60) = 8.00 40 + 60 = 100 2 6 = 8 + 40 + 60 = 100 solutions works
Algebra Word Problem: Coins
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Algebra Word Problem Tutor: Coin & Money Problems $28.66 The Algebra Word Problem Tutor series teaches by examples how to set up algebra word problems and solve them. This program teaches students how to solve word problems that involve coin and money. Students are taught how to read the problem and what keywords to look for to gain clues on how to proceed and solve the problem. Students are then taught, for each problem how to set up the appropriate al… |
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Algebra Word Problems – Ages and Coins $15.99 … |
