Algebra Problems Eighth Grade
How to solve a system of equations?
I just started Algebra Advanced Geometry after taking last year. I am a second year student, I have not dealt with since the eighth grade algebra. For our first day in Adv. Algebra we had a fix for the task. There are some things I need to run my memory, but a "system of equations" I can not even begin to remember. The problems are defined as follows: "In the years 33 and 34, solve the system of equations .. "33 x = 3y + 2x + y-1 = 8 34. 5x + y = 9 2x + 3y = 1 How can I solve this problem? Explanation not only answers would be greatly appreciated.
First one ……… x – 3y = 1 (multiplied by -2 )……….( 1)-2x + y = 8 ……….( 2) equation (1) becomes 6-2x y =- 2x + y-2 = 8 + —– ————— – - ——- ————- 0x =- 2 =- 5 10 and substituting in the equation y =- 2 (1) x – 3y = 1 x-(3 *- 2) = 1 x 6 = 1 x =- 5 second ……… 5x + y = 9 ……..( 1) 2x + 3y = 1 ……….( 2) by multiplying equation 1 by 3 15x 3 = 27 and 2x + 3y = 1 ——————- – - – —– ————– 13X 0 y = 26 x = 2 and substituting x = 2 in (a) y = 5x + 9 + 9 5 * 2 = 9-10 = OO and =- 1. Answers equation …. 1. x =- 5 …… =- 2 and 2. x = 2 ……. and =- 1.
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