Algebra Problems For 5th Graders
An incredible math problem my little son in the 4th grade.?
I can not believe, but this problem has been given to students 4th year as extra credit. I am a mathematician in the family and called me and solved it, but only by trials and errors. Can anyone tell me what is the equation to solve this problem. I think there are two unknowns and somehow I just with an equation .. Hmmm only. John has two digit numbers. Jane has two digit numbers and everyone is even more than John. The product of the multiplication of numbers and Jane is 12 more than the product of double digit Johns. What are the numbers? Well, turns out to be John are 5 and 6, while Jane is 6 and 7. But how you doing to that in algebra? I tried but could not solve. (Axb) = ((A +1) x (b +1)) – 12
Juan Figures A and B by Jane figures: c = a +1 and D = 1 b (a 1) (b +1) = 12 + ab ab + a + b 1 + AB = 12 a + b = 11 A and B are less than 9 because a + b + 1 1 is less than 10 3 + 8 = 11 John: 3 * 8 = 24 Jane: 4 * 9 = 36 (12 more than John) 4 + 7 = 11 John: 4 * 7 = 28 Juana: 5 * 8 = 40 (12 more than John) 5 + 6 = 11 John: 5 * 6 = 30 Jane: 6 * 7 = 42 (12 more than John) So the pairs of numbers for John can be: (3.8) (4.7) (5, 6) and satisfy the requirements problem. If you're not supposed to be a unique solution, then there is something missing in the problem statement.
5th Grade Advanced Math Students Reach Consensus
