Algebra Math Help

help with solving (please show the steps) three algebra practice problems for a test tomorrow…?

solve: -4(2x-6) + 7x = 5x + 24

- 4(2x – 6) + 7x = 5x + 24
- 8x + 24 = – 2x + 24
6x = 0
x = 0

Answer: x = 0

Proof:
- 4(2[0] – 6) + 7(0) = 5(0) + 24
- 4(0 – 6) + 0 = 0 + 24
- 4(- 6) = 24
24 = 24
————
√(3x + 7) = 3x + 5
9x² + 15x + 15x + 25 = 3x + 7
9x² + 27x = – 18
x² + 3/2x = – 2 + (3/2)²
x² + 3/2x = – 8/4 + 9/4
(x + 3/2)² = 1/4
x + 3/2 = ± 1/2

x = 1/2 – 3/2, x = – 2/2, x = – 1
x = – 1/2 – 3/2, x = – 4/2, x = – 2

Answer: x = – 1, – 2

Proof (x = – 1):
√(3[- 1] + 7) = 3(- 1) + 5
√(- 3 + 7) = – 3 + 5
√4 = 2
2 = 2

Proof (x = – 2):
√(3[- 2] + 7) = 3(- 2) + 5
√(- 6 + 7) = – 6 + 5
√1 = – 1
± 1 = – 1
————-
x² + 6x + 16 < 8
x² + 3x < - 8 + 3²
x² + 3x < 1
(x + 3)² < 1
x + 3 < ± 1

x < 1 - 3, x < - 2
x < - 1 - 3, x < - 4

Answer: x < - 2, - 4

ACT Math: Algebra Problem