Hard Algebra Questions
Can someone please help with this Hard Algebra Question?
For positive integers a1 ,…, 1N Let (a1 ,…, a) and [a ,..., a] be your g.cd. and LCM, respectively. Show that xyz = (yz, zx, xy) [x, y, z] Can anyone help would be greatly appreciated. Note: A1 is an index and a peer, a n is an index
Imagine x, y, written as the product of powers of primes. We will show that for every prime number p of the formula works, and if it works for arbitrary x, y, z. That is, the situation is reduced to x = Y p = ^ p ^ p ^ bz = c, where p is a prime. We need to know the size of a, b, c, but is arbitrary. Tell a> b> = c. Then (zy, zx, xy) = p ^ (b + c) and [x, y, z] = p ^ a. While their product is xyz.
Algebra Factoring SAT Math Problem Hard NLC
