Instant Algebra Answers
(10 POINTS RIGHT AWAY) What is the inverse of this function?
f (x) = 3. (Sen (4x-1)) ^ 2 f (x) = Ln ((x ^ 2 + 4x + 1) ^ 2) And one more question, to simplify the table below using the laws of algebra proposition (RVP) ^ (~ rv (p ^ q)) ^ (rvq) I found the answer is r ^ p ^ q Is that true?? THX B4 .. I'll give u 10 points if u can help me … OTHER PEOPLE plz give me detail other solutions …. Bcause I'm A MATH NEWBIE … THX B4
OK … we will see f (x) = y = 3 (sin (4x-1)) ^ 2 and divide by 3 / 3 = [sin (4x-1)] ^ 2 take the square root (Y / 3) ^ (0.5) = sin (4x-1) to inverse sine inverse_sine [(Y / 3) ^ (0.5)] = 4x-1 add [inverse_sine (s / 3) ^ (0.5)] + 1 = 4x divide by 4 and get the result x = [Inverse_sine [(Y / 3) ^ (0.5)] +1] / 4 second issue to raise the exponent and both sides of the equation exp (y) = [x ^ 2 +4 x + 1] ^ 2 take square root [exp (y)] ^ (0,5) = x ^ 2 + 4x + 1 to add three to both sides of the equation [exp (y) ^ (0.5)] +3 = x ^ 2 +4 X 4 resolve the exp [quadratic (y) ^ (0.5)] 3 = (X +2) ^ 2 Take the square root of both sides [[exp (y) ^ 0.5)] 3] ^ 0.5 = (x +2) 2 subtract on both sides and your response [[exp (y) ^ (0.5)] 3] ^ (0.5) -2 x = Good luck!
Abstrakt Algebra – Stigmata
