Algebra Math Help

Pre Algebra Holt

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PLEASE HELP! So confused! solve the equations w / variables of both sides?

Can someone help me with some. "I can walk through it. 1) 5x-1 = March 21 x 2) = 6y three 9Z-15 3) 3 = 7w-W-12, June 4) 12 8 = 3a-May 3) 2 / 9n-5 = 2 5 / 9n 6) = 1.8d 31 3.4d 19 July) 2b 4b 30 = 3 = 2x 4x 2.3-3.7 9) 3 (M-5) = M-7 10) 5 (3h-2) = two (8 h) 11) 5 1 / 2y = 6 3/8y 12) 2 (x-1 / 2) = 4 (x +1 / 4) 13) 4 (3R -2) = 4-12R 14) = 1/3x 1/4x-7 August 1915) 3a-4 / 2 = 5 is Holt Pre-2a Algebra-task and a practical lesson 10-3

I do not know if it refers to two different variables for the second problem or not. Anyway, what to do first is get variables on the same side. For example: 1. 5x-1 = 3 x 21 First, subtract 3 times on both sides to get the variables on the same side of =. This gives: 2x-1 = 21, then get rid of any number added or subtracted to / from the variable (we'll get rid of one) of do the opposite action (if it is -1, then one, etc.): 2x = 22 Finally, get rid of this number before the variable is multiply or divide. In this case, you divide by 2 since the original equation is multiplication. You still have to face and action must be done on both sides the =. Divide by 2: x = 11 I hope I explained well. Feel free to contact me if you need help!